# Calculation of bricks quantities in 1 CFT Wall & in a room

In this short construction article, you will get some quick tricks to measure the numbers of bricks in a masonry wall per cubic foot.

The calculation is made on the basis of the following dimensions :-

- Length (L) of bricks in CFT is taken as 0.75 ft.
- Width (W) of bricks in CFT is taken as 5 inches or 0.41 ft.
- Thickness (T) of Bricks in CFT is taken as 3” or 0.25 ft.

To determine the volume of brick in 1 CFT, multiply Length, Width and Height.

Now, take volume as V.

So, V = L x W x T = 0.75 x 0.41 x 0.25 = 0.076 ft^{3}

Therefore, total numbers of brick in 1 CFT = 1/0.076 = 13.15 bricks

Suppose, the mortar comprises of 10% area.

So, 13.15 x 10/100 = 1.315

So, the total numbers of bricks without mortar = 11.835

Suppose, 5% wastage is occurred in bricks.

So, 11.835 x 5/100 = 0.591

Therefore, total numbers of bricks in 1 CFT = 11.835 + 0.591 = 12.426 or 12.5 (approx)

So, in 1 CFT, the numbers of bricks required = 12.5

Now, calculate the numbers of bricks in a room with area 10 ft x 5 ft.

So, the area of the room = 10 x 5 ft.

As there are two walls inside the room, so it is required to determine the volume for both the walls.

### For Wall (1)

- Length (L) of one side wall is taken as 10 ft
- Width (W) of bricks is taken as 0.25 ft
- Height (H) of the wall is taken as 10 ft
- Volume of wall in cft = L x W x H = 10 x 0.25 x 10 = 25 ft
^{3} - For both side= 2 x 25 = 50 ft
^{3}

### For Wall (2)

- Length (L) of second wall is taken as 5 ft
- Width (W) of bricks is taken as 0.25 ft
- Height (H) of the wall is taken as 10 ft
- Volume of wall in cft = L x W x H = 5 x 0.25 x 10 = 12.5 ft
^{3} - For both sides = 2 x 12.5 = 25 ft
^{3}

So, sum of the volume of both walls = 50 ft3 + 25 ft3 = 75 ft^{3}.

From previous calculation, we get 1 CFT = 12.5 bricks

So, numbers of bricks for 75 CFT = 12.5 x 75 = 937.5 bricks

So, the numbers of bricks necessary for building up 10 x 5 ft room = 937.5